Thursday, May 29, 2014

The Mole Project

Avogadro's number is related to any mole substance because the number that Avogadro made was to convert particles into moles of any substance. The number is..... 6.022 x 10^23.
 
 

Converting a recipe from moles to standard cooking measurements

This table is used to adjust the following recipes:       
                                   Moles                 Grams
Flour                            2.66               319.47664 
baking soda                0.0335             2.814201
salt                              0.036              2.103948
butter                          1.084              236.53422
sugar                           0.44                150.61068
brown sugar                0.31                106.11207
eggs                            0.624              99.947952
vanilla                         0.062               9.433238
chocolate chips            2.82                338.69328

Recipe of ANZAC Biscuits:

In this recipe, 0.63 moles of water has been reduced to 0.45 moles of water.
 .63
------ = 1.4%
 .45
So by using the percent yield I am going to calculate the changes that need to be made.

The adjusted recipe would be:
Flour: 1.9 moles
Rolled oats: 1.26 moles
Brown sugar: 1.26 moles
shredded coconut: 1.06 moles
Almonds: 0.68 moles
Cranberries: 0.69 moles
Butter: 0.85 moles
Honey: 0.64 moles
water: 0.45 moles

Oatmeal Chocolate Cookies:

In this recipe, 0.72 moles of Rolled Oats has been reduced to 0.50 moles of Rolled Oats.
 0.72
-------- = 1.44%
 0.50
So by using the percent yield I am going to calculate the changes that need to be made.

The adjusted recipe would be:
Flour: 2.96 moles
Rolled Oats: 0.5 moles
Butter: 2.625 moles
Eggs: 1.3 moles
Walnuts: 0.53 moles
Sugar: 1.74 moles
Brown Sugar: 1.91 moles
Chocolate Chips: 2.64 moles
Baking Soda: 0.17 moles
Vanilla: 0.14 moles

Chocolate Chip Cookies:

In this recipe, 3.8 moles of Chocolate Chips has been reduced to 2.5 moles of Chocolate Chips

The ratio is 1.52

Flour:  4.8
Coco Powder: .697
Butter: 2.48
Eggs: .5
Walnut: .5
Sugar: 2.20
Brown Soda: .164
Vanilla: .131

Drop Sugar Cookies with Walnuts:

In this recipe, 5.33 moles of flour has been reduced to 4.33 moles of flour.

The ratio is 1.23

Flour: 4.31
Butter: 1.91
Eggs: .39
Walnuts: .78
Sugar: 3.40
Baking Soda: .203
Vanilla: .252

1. You want to 6 make grilled cheese sandwiches (use the equation below, Bd = bread and Ch = Cheese) and you have 13 slices of bread and 5 slices of cheese. How may grilled cheese sandwich can you make? And what is the limiting reagent?
                                                            2Bd + Ch→Bd2Ch
You have 13 slices of bread
You have 5 slices of cheese
                                                                               13
You need 2 slices of bread to make 1 sandwich, so ----  is 6.5. You can make 6 sandwiches with the bread.
                                                                                2
                                                                             5
You need 1slice of cheese to make 1sandwich, so --- is 5.You can only make 5sandwiches with the cheese.
                                                                             1
The limiting reactant is cheese.


2. You are having some friends over for dinner you want to make 8 cheese burgers, you have 8 hamburger patties, 12 bums, 7 slices of cheese, 18 slices of tomato, 16 pieces of lettuce and 9 slices of onion. Use the equation below (where buns = B, hamburger patty = H, cheese = Ch, tomatoes = T lettuce = L and onion = O) to determine how many cheese burgers you can make (what’s your theoretical yield?) and what the limiting reagent is? Hint you may need to balance the equation first.
                                               B+ H+ Ch+ 2T+ 2L+O → BHChT2L2O

Considering  cheese is the limiting reagent and there are only 7 slices of  them you can only make 7 sandwiches.

3. Balance the chemical equations below. Find the limiting reagent and the theoretical yield if there is one gram of each reagent.

 
 

Sources:

Ms. Del Bosque 

Wednesday, May 7, 2014

Boyle's Law

Robert Boyle is what the Boyle's Law is named after.

In 1655, Boyle moved to Oxford where he made Robert Hooke his assistant and together they constructed the most famous piece of experimental equipment related with Boyle, the vacuum chamber or air-pump.

This law appears in an appendix written in 1662 to his work New Experiments Physio-Mechanical, Touching the Spring of the Air and its Effects in 1660 (Hunter).

This law describes the relationship between pressure and volume of gases, so if the pressure is doubled then the volume will be halved.
 

Some examples of the relationship between pressure and volume are:
-The bubbles exhaled by a scuba diver grow as the approach the surface of the ocean. (The pressure exerted by the weight of the water decreases with depth, so the volume of the bubbles increases as they rise.) 
-Deep sea fish die when brought to the surface. (The pressure decreases as the fish are brought to the surface, so the volume of gases in their bodies increases, and pops bladders, cells, and membranes). 

 This is a graph of the relationship between volume and pressure.

This law determines that for the same amount of a gas at constant temperature, P*V=constant.
P = pressure (measured in atm)
V = volume (measured in Liters)
 This equation is derived from the Ideal Gas Law equation P * V = n * R * T
                                                                                              ^      ^           ^
                                                                                 pressure x volume = constant

Example problem:
A gas has a pressure of 1.01 atm and occupies a volume of 6.4 L. If the gas is compressed to a volume of 1.05 L, what will its pressure be, assuming constant temperature? Answer in units of atm.
                                  Explanation:
V1 = 6.4 L                                                                                          V1 = 1.05 L
P2 = 1.01 atm                                                                                     P2 = ?
                                 Applying Boyle's Law,
P1V1 = P2V2
         P1 V1          (1.01 atm) (6.4 L)
P2 =  ------   =    --------------------
          V2                    1.05 L
     = 6.15619 atm

 Sample problems:
1. The initial pressure was 3 atm while the volume was 2 L. What would the volume be if  the pressure rose to 6 atm?

2. The initial pressure was 380 atm while the volume was 6 L. What would the volume be if  the pressure rose to 760 atm?

3.  The initial pressure was 5.2 atm while the volume was 0.555 L. What would the pressure be if  the volume rose to 2.14 atm?

4. The initial volume and pressure of the gas is 2L, 3 atm. Assuming the temperature and moles of gas is constant, what is the pressure if the volume is reduced to 1.25 L?

5. Four liters of carbon dioxide have a pressure of 1.5 atmospheres. If the original pressure was .9 atmospheres, what was the original volume?


Answer Key:
1. V2 = 1L
2. V2 = 3L
3. P2 = 1.349 atm
4. P2 = 4.8 atm
5. V₁= 6.666... L

sources: